Ran Van Vo
The author used the new formulas in first book "Fermat's Last Theorem" for solving the Diophantine Equations which have the forms:
x'n + y'n = cz'n
ax'n + by'n = cz'n
ax'n + by'p = cz'q
And more methods for more the Diophantine equations--
Special : I used the zeta function ζ(1) is not equal to zero for solving these Diophantine equations, which is elementary, and the author thinks that every Student and Reader, will easily be able to do them...
Ran Van Vo was born May 1945 in Quang Ngai, Vietnam
Before 1975 he was an officer in the South Vietnam Army during the Civil War.
After 1975 the Communists took over the South Vietnam, and he was placed in jail for three years.
In 1989 he applied for HO-- a refugee program in United States, and he got a reply from the American Embassy saying that they accepted his request.
In 1990 his family had six people,(his wife : Sen Thi Tran, two daughters and two sons) and they have started a new life in Houston, TX, in the United States. A year after living in the United States, he became interested in the World of mathematics; about Fermat's Last Theorem. Thus, in March 2002, he began his quest for knowledge in mathematics.
He is now living in Wichita, KS.
Today we have advances in science, and society has become more and more and more technological. It seems that we are contented with the present knowledge that we have obtained in school, however, we are still far from reaching our goal. For example, in the past an arrowhead hit a target; we considered it a success. Today if a rocket hits in one area that is not good enough; it has to land in five or ten different areas. The same can be said for mathematics. If we want to find a solution to an unknown, we must have an equation. For two unknown we must have two equations and so on... If we have an equation with more than one unknown:
Example :
(a2 + b2)(c2 + d2) = u2 + v2
(a4 + b4)(c4 + d4) = u2 + v2
(a6 + b6)(c6 + d6) = u2 + v2...
x2 + y2 = z4
x2 + y2 = z6
x2 + y2 = z8 ...
x3 + y3 + z3 = k
(k is a non-zero integer)
xn + yn = czn
xn + byn = zn
axn + yn = cn
axn + byn = czn
axn + byp = czq ....
( 1/m + 1/ n + 1/ p 1)
If there is an equation with more than one unknown, then can anyone solve it? It is going be very difficult! Could a calculator and computer aid us in finding the solution to an equation with more than one unknown? Of course not! However, the book "Fermat’s Last Theorem" by Ran Van Vo could show us how to solve it in a very easy manner.
It sometime takes a few minutes to solve it because in this book there are many new formulas that could help us in solving the equation. I believe that there are many different ways of solving this problem besides my method.
The Mathematics convention in France of May 2000 had come up with seven problems of the millennium. One of the seven problems was the Birch and Swinnerton Dyer Conjecture that I have solved in the book "Fermat's Last Theorem". In fact "the Birch and Swinnerton Dyer Conjecture asserts that the size of the group of rational points is related to the behavior of an associated zeta function ζ(s) near the point s = 1. In particular this amazing conjecture asserts that if ζ(1) is equal to 0, then there are an infinite number of rational points (solutions), and conversely, if ζ(1) is not equal to 0, then there is only a finite number of such points"
And the Fermat Last Theorem there are no positive integers such as xn + yn = zn for n > 2 . Here are two different talking about problems, but I think that there is a method for to prove it. Welcome to my proving in "Fermat’s Last Theorem" by Ran Van Vo
This book will prove the Diophantine equations in Mathsoft about Fermat’s Last Theorem. On a Generalized Fermat-Wiles Equation (www.mathsoft.com/asolve/fermat/fermat.htm) In part Reference of On a Generalized Fermat-Wiles Equation ...
In fact, I’m fascinating by Fermat’s Last Theorem, but my knowledge is limited, of course, sometime my work is incorrect, please let me know by email (vo_ran@hotmail.com), I will fix any errors.
